3x^2+90x-1800=0

Solution for 3x^2+90x-1800=0 equation:

3x^2+90x-1800=0

a = 3; b = 90; c = -1800;
Δ = b2-4ac
Δ = 902-4·3·(-1800)
Δ = 29700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{29700}=\sqrt{900*33}=\sqrt{900}*\sqrt{33}=30\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-30\sqrt{33}}{2*3}=\frac{-90-30\sqrt{33}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+30\sqrt{33}}{2*3}=\frac{-90+30\sqrt{33}}{6}
$